Hey There Braintrust,

So I looked at the fuse block and #16 (the rear power outlet) is a 20AMP fuse. According to my math, that means the max AC wattage (via an inverter) it can handle would be a 264 Watt output...right?

Here's my formula (trying to solve for x):

x WattsAC ÷ 12 x 1.1 = 20amps

...based on the formula: AC Watts ÷ 12 x 1.1= DC Amps

Highschool was a loooong time ago, so be easy on me!

-p

_________________
2006 CRD w/99,300 miles
F31 from a previous life
EHM @ 42K, ProVent @ 79K
GDE Eco Tune & TCM @ 46K
Engine mounts replaced @ 55k/93k, Timing Belt @ 90k
Lift Pump @ 97k
OME Lift, 1.5''
Kenwood TM-V71 Ham Radio / Cobra C75WX CB
Surf Racks

No, at 20 amps you have 240 watts (12x20)
On the Ac side from the inverter is limited to 240 watts less about a 20% loss due to inefficiency of the inverter. So the inverter would be about 200 watts max.